(x-5)(x^2+4x-2)=0

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Solution for (x-5)(x^2+4x-2)=0 equation: 


Simplifying
(x + -5)(x2 + 4x + -2) = 0

Reorder the terms:
(-5 + x)(x2 + 4x + -2) = 0

Reorder the terms:
(-5 + x)(-2 + 4x + x2) = 0

Multiply (-5 + x) * (-2 + 4x + x2)
(-5(-2 + 4x + x2) + x(-2 + 4x + x2)) = 0
((-2 * -5 + 4x * -5 + x2 * -5) + x(-2 + 4x + x2)) = 0
((10 + -20x + -5x2) + x(-2 + 4x + x2)) = 0
(10 + -20x + -5x2 + (-2 * x + 4x * x + x2 * x)) = 0
(10 + -20x + -5x2 + (-2x + 4x2 + x3)) = 0

Reorder the terms:
(10 + -20x + -2x + -5x2 + 4x2 + x3) = 0

Combine like terms: -20x + -2x = -22x
(10 + -22x + -5x2 + 4x2 + x3) = 0

Combine like terms: -5x2 + 4x2 = -1x2
(10 + -22x + -1x2 + x3) = 0

Solving
10 + -22x + -1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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